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5x^2-23x=-18
We move all terms to the left:
5x^2-23x-(-18)=0
We add all the numbers together, and all the variables
5x^2-23x+18=0
a = 5; b = -23; c = +18;
Δ = b2-4ac
Δ = -232-4·5·18
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-13}{2*5}=\frac{10}{10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+13}{2*5}=\frac{36}{10} =3+3/5 $
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